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Module 7 sur 8 90m 15 exam Qs

Energy Efficiency

AC and heat pump energy efficiency analysis including SEER2 vs. EER comparisons, runtime calculations, thermostat setback strategies, zoning systems, and whole-house efficiency optimization.

  • Compare SEER2 and EER2 efficiency metrics and their appropriate applications
  • Calculate estimated annual energy costs using equipment efficiency ratings
  • Evaluate thermostat strategies and their impact on energy consumption
  • Assess zoning system benefits and limitations for residential applications

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Understanding Efficiency Ratings

SEER2 vs. EER2 - What They Tell You

Residential AC and heat pump efficiency is expressed using two primary metrics, and understanding the difference is critical for making sound recommendations to homeowners.

SEER2 (Seasonal Energy Efficiency Ratio) measures cooling efficiency across an entire season. It is calculated at the M1 test conditions with 0.50 IWC external static pressure and represents a weighted average of efficiency at multiple outdoor temperatures from 65 F to 104 F. SEER2 favors equipment that performs well at part-load conditions because most of the cooling season involves mild to moderate weather, not peak conditions.

EER2 (Energy Efficiency Ratio) measures cooling efficiency at a single peak condition - 95 F outdoor, full-load operation. EER2 represents the equipment's performance during the hottest conditions when the system runs at or near full capacity.

SEER2 - Seasonal Average

Test conditions: Multiple outdoor temps (65-104 F)

Measures: Average seasonal cooling efficiency

Favors: Part-load efficient equipment (variable-speed)

Best for: Mild to moderate climates

Federal minimum: 13.4-14.3 (region-dependent)

EER2 - Peak Performance

Test conditions: 95 F outdoor, full load

Measures: Peak-condition cooling efficiency

Favors: Equipment with strong full-load performance

Best for: Hot climates (Phoenix, Dallas, Houston)

Typical values: 10.0-13.0 for residential

Calculating Annual Energy Cost

Estimated annual cooling energy cost helps homeowners understand the financial impact of efficiency differences:

Annual Cooling Cost = (Cooling Load in BTU) / (Efficiency in BTU/Wh) x (Electricity Rate in $/kWh) / 1,000

A simplified approach using seasonal cooling hours:

Annual Cost = (Capacity BTU/h x Annual Cooling Hours) / (SEER2 x 1,000) x $/kWh

Equipment Capacity SEER2 Annual Hours Annual kWh Annual Cost ($0.14/kWh)
Old unit 36,000 BTU/h 10.0 1,500 5,400 $756
Minimum new 36,000 BTU/h 14.3 1,500 3,776 $529
High-efficiency 36,000 BTU/h 20.0 1,500 2,700 $378
$227/yr
Savings: 10 SEER to 14.3 SEER2
$378/yr
Savings: 10 SEER to 20 SEER2
30%
Typical Savings from Upgrade

The Efficiency Gap

Published efficiency ratings represent laboratory performance under ideal conditions. Real-world performance is often significantly lower due to:

  • Incorrect refrigerant charge - 10% undercharge reduces efficiency by 5-7%
  • Low airflow - 20% low airflow reduces efficiency by 10-15%
  • Duct leakage - 25% duct leak wastes 15-25% of energy
  • Dirty coils - Dirty condenser or evaporator reduces efficiency by 5-15%
  • High static pressure - Excessive restriction forces the blower to work harder

A 16 SEER2-rated system with incorrect charge, low airflow, and leaky ducts might actually perform at the equivalent of 10-12 SEER2. This is why BPI emphasizes testing and correcting these factors before recommending equipment upgrades.

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Fix Before Replacing

Correcting charge, airflow, and duct leakage on an existing 13 SEER system can improve its actual performance by 20-30% - equivalent to the savings from upgrading to a new 16 SEER2 unit. Always optimize the existing system before recommending replacement. The cheapest ton of cooling is the one you already have but are not using effectively.

Key Takeaway

SEER2 measures seasonal average efficiency (best for mild-moderate climates) while EER2 measures peak-condition efficiency (important for hot climates). Real-world efficiency is often 20-40% below published ratings due to charge, airflow, and duct problems. Correcting these problems on an existing system can save as much energy as upgrading to higher-efficiency equipment.